The only way around this is to place the result of func_get_args() in a variable and then pass that variable to the function you were calling in the first place instead of func_get_args().
WON'T WORK:
my_func(func_get_args());
WILL WORK:
$func_args=func_get_args();
my_func($func_args);
This is because the func_get_args() function must get called in the right context to return the right values as explained in the PHP documentation (PHP.net func_get_args):
Note: Because this function depends on the current scope to determine parameter details, it cannot be used as a function parameter. If this value must be passed, the results should be assigned to a variable, and that variable should be passed.
Interesting.
Thoughts?
